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  4. Propene on reaction with methylene iodide in presence of Zn-Cu couple gives:

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Q. Propene on reaction with methylene iodide in presence of $Zn-Cu$ couple gives:

Hydrocarbons

Solution:

$CH_3CH = CH_2 + CH_2 I_2 \xrightarrow{Zn} \underset{CH_2}{CH_3 - CH - CH_2}$