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  4. Production of iron in blast furnace follows the following equation Fe 3 O 4( s )+4 CO ( g ) arrow 3 Fe ( l )+4 CO 2( g ) when 4.640 kg of Fe 3 O 4 and 2.520 kg of CO are allowed to react then the amount of iron (in g ) produced is: [Given: Molar Atomic mass ( g mol -1): Fe =56 Molar Atomic mass ( g mol -1): 0=16 Molar Atomic mass ( g mol -1):= C =12

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Q. Production of iron in blast furnace follows the following equation
$Fe _{3} O _{4}( s )+4 CO ( g ) \rightarrow 3 Fe ( l )+4 CO _{2}( g )$
when $4.640\, kg$ of $Fe _{3} O _{4}$ and $2.520 \,kg$ of $CO$ are allowed to react then the amount of iron (in $g$ ) produced is :
[Given : Molar Atomic mass $\left( g mol ^{-1}\right): Fe =56$
Molar Atomic mass $\left( g mol ^{-1}\right): 0=16$
Molar Atomic mass $\left( g mol ^{-1}\right):= C =12$

JEE MainJEE Main 2022Some Basic Concepts of Chemistry

Solution:

Moles of $Fe _{3} O _{4}=\frac{4.640 \times 10^{3}}{232}=20$
Moles of $CO =\frac{2.52 \times 10^{3}}{28}=90$
So limiting Reagent $= Fe _{3} O _{4}$
So moles of $Fe$ formed $=60$
Weight of $Fe =60 \times 56=3360\, gms$