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Q. Primitive of $\frac{3 x^4-1}{\left(x^4+x+1\right)^2}$ w.r.t. $x$ is :

Integrals

Solution:

$\int \frac{\left(3 x^4-1\right)}{x^2\left(x^3+1+x^{-1}\right)^2} d x=\int \frac{\left(3 x^2-x^{-2}\right)}{\left(x^3+1+x^{-1}\right)^2} d x$