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Q. Predict the position of an element has the electronic configuration $1 s^{2}\, 2 s^{2}\,2 p^{6} \,3 s^{2} \,3 p^{6} \,3 d^{5} \,4 s^{1}$.

Classification of Elements and Periodicity in Properties

Solution:

As $n=4$, hence element lies in $4^\text{ th}$ period.
Group number $=n s+(n-1) d=1+5=6$
So, the given element position is period $4$ and group $6$.