Thank you for reporting, we will resolve it shortly
Q.
Power dissipated across the $8 \,\Omega$ resistor in the circuit shown here is $2$ watt. The power dissipated in watt units across the $3 \,\Omega$ resistor is :-
As voltage drop across
$8 \Omega=\sqrt{2 \times 8}=4 V \left(\because P =\frac{ V ^{2}}{ R }\right)$
Therefore voltage drop across $3 \Omega=3 V$
$[\because 4 V$ is divided in ratio of resistances between $1 \Omega$ and $3 \Omega]$
Hence power dissipated in $3 \Omega=\frac{(3)^{2}}{3}=3$ watt
