Q. Potential at any point inside a charged hollow, sphere
JamiaJamia 2006
Solution:
Key Idea: If a charge is taken from one point to another inside a charged spherical shell no work is done. The electric field inside a spherical charge is zero everywhere.
Since, $ E=-\frac{dV}{dx} $ $ \therefore $ $ E=0,\Rightarrow \frac{dV}{dx}=0 $
$ \Rightarrow $ V = constant. The value of potential at spherical shell is given by $ V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{K}volt $ Its value is same as that on the surface. Note: Outside the shell both E and V decrease with distance, E decreases rapidly $ \left( \propto \frac{1}{{{r}^{2}}} \right) $ and decreases compactly slowly $ \left( \propto \frac{1}{r} \right) $ .
