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  4. Potassium iodide reacts with acidified K 2 Cr 2 O 7 . Number of moles of KI required for one mole of K 2 Cr 2 O 7 is .

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Q. Potassium iodide reacts with acidified $K _{2} Cr _{2} O _{7} .$ Number of moles of $KI$ required for one mole of $K _{2} Cr _{2} O _{7}$ is _____.

The s-Block Elements

Solution:

$[Cr_2O_7^{2-} + 14 H^+ + 6e^- \to 2Cr^{3+} + 7H_2O]$

$[2I^- \to I_2 + 2e^- ] \times 3$

$Cr_2O_7^{2-} + 14 H^+ + 6I^- \to 2Cr^{3+} + 7H_2O + 3I_2$

$1$ mole of $K_2Cr_2O_7$ reacts with $6$ moles of $KI$.