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Q.
Polonium (atomic mass $= 209$) crystallises in a simple cubic structure with a density of $9.32\,g\, cm^{-3}$ Its lattice parameter (in pm) is closest to
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Solution:
Given,
density of polonium $=9.32\, g\, cm ^{-3}$
As we know, $\rho=\frac{M \times Z}{V \times N_{A}}$
where, $\rho=$ Density
$M=$ Mass of the element
$Z=$ Number of atom in a unit lattice
$V=$ Volume
$N_{A}=$ Avogadro's number
For scc, $Z=1$
$\therefore 9.32=\frac{209 \times 1}{a^{3} \times 6.022 \times 10^{23}}$
$a^{3} =37.2 \times 10^{-24}$
$a =3.33 \times 10^{-8} cm \approx 334\, pm$