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Q.
$pK_a$ of $CH_3COOH$ is 4.74. The pH of 0.01 M $CH_3COONa$ is
Equilibrium
Solution:
$CH_{3}COONa$ is a salt of a weak acid and strong base
$\therefore PH =7+\frac{1}{2}[PK_{a}+log\,C]$
$=7+\frac{1}{2} [4.74+log\,0.01]$
$=7+\frac{1}{2} [4.74-2]$
$=8.37$