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Q. $pK_a$ of a weak acid is $5.76$ and $pK_b$ of a weak base is $5.25$. What will be the $pH$ of the salt formed by the two?

Equilibrium

Solution:

$pH=\frac{1}{2}\left[pK_{w}+pK_{a}-pK_{b}\right]$
$pH=7+\frac{1}{2}\left(5.76-5.25\right)$
$=7.255$