Lateral shift $L _{ s }$; $L _{ s }= t \frac{\sin ( i - r )}{\cos r }$
Normal shift $L _{ n }$
$L _{ n }= t \left[ 1 -\frac{1}{\mu}\right]$
$L _{ n }= t \left[ 1 -\frac{1}{\mu}\right]$
$\mu$ refractive index.
From the equations option $A , C , D$ are correct. And $B$ is the wrong statement.