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Q. Photons with energy $5 \,eV$ are incident on cathode $C$ in a photoelectric cell. The maximum energy of emitted photoelectrons is $2 \,eV$. When photons of energy $6 \, eV$ are incident on $C$, no photoelectrons will reach anode $A$; if the stopping potential (in volt) of $A$ relative to $C$ is (only magnitude)

Dual Nature of Radiation and Matter

Solution:

$e V_{s}=\frac{1}{2} m v_{\max }^{2}=h v-\phi_{0}$
$2-5-\phi_{0} $
$\Rightarrow \phi_{0}=3 eV$
In second case,
$e V_{s}=6-3=3 \,eV $
$\Rightarrow V_{s}=3\, V$
$\therefore V_{A C}=-3\, V$