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  4. Photons of energy 6 eV are incident on a potassium surface of work function 2.1 eV. The stopping potential will be

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Q. Photons of energy $6 \,eV$ are incident on a potassium surface of work function $2.1 \,eV$. The stopping potential will be

Haryana PMTHaryana PMT 2011

Solution:

$E_{k}=h v-\phi=6-21=3.9\, eV$
Stopping potential $\frac{E_{k}}{e}=-\frac{3.9 \,eV }{ e }$
$=-3.9 \,V$