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Q. Photon is quantum of radiation with energy $E=h v$ where $v$ is frequency and $h$ is Planck's constant. The dimensions of $h$ are the same as that of

Physical World, Units and Measurements

Solution:

From $E=h v$
$h=\frac{E}{v}=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ T ^{-1}\right]}$
$=\left[ ML ^{2} T ^{-1}\right]$
Angular impulse
$=\tau \times t=\left[ ML ^{2} T ^{-2} \times T \right]$
$=\left[ ML ^{2} T ^{-1}\right]$
Angular momentum
$=m v r=M\left[ LT ^{-1}\right] L$
$ =\left[ ML ^{2} T ^{-1}\right]$