(a) Phosphorous pentachloride $\left( PCl _{5}\right)$ has a trigonal bipyramidal structure. Here, the five bonds are not of equal lengths as the axial bonds are slightly longer than the equatorial bonds.
(b) $PCl _{5}$ solid exists as $\left[ PCl _{4}\right]^{+}$ and $\left[ PCl _{6}\right]^-$ and they have tetrahedral and octahedral structures respectively.
(c) On hydrolysis, $PCl _{5}$ gives $H _{3} PO _{4}$ which is tribasic.
$PCl _{5}+4 H _{2} O \rightarrow H _{3} PO _{4}+5 HCl$
In $H _{3} PO _{4}, P$ is in its $+5$ oxidation state. So it is in its highest oxidation state and hence is not a good reducing agent.