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  4. Phosphorus pentachloride dissociates as follows, in a closed reaction vessel, PCl,5(g) leftharpoons PCl3(g) + Cl2(g) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl5 is x, the partial pressure of PCl3 will be:

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Q. Phosphorus pentachloride dissociates as follows, in a closed reaction vessel,
$PCl,_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$
If total pressure at equilibrium of the reaction mixture is $P$ and degree of dissociation of $PCl_{5}$ is $x$, the partial pressure of $PCl_{3}$ will be:

Equilibrium

Solution:

$\underset{\overset{1}{1-x}}{PCl_{5(g)}} \rightleftharpoons \underset{\overset{0}{x}}{PCl_{3(g)}} +\underset{\overset{0}{x}}{Cl_{2(g)}}$
$\therefore K_{c}= \frac{x^{2}}{1-x}\left[\frac{P_{eq}}{1+x}\right]$
Also $Ppcl_{3}=\frac{P_{eq}.x}{\left(1+x\right)}$