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  4. Phosphorus pentachloride dissociates as follows in a closed reaction vessel, PCl5(g) leftharpoons PCl3(g)+Cl2(g) If total pressure at equilibrium of the reaction mixture is p and degree of dissociation of PCl5 is x, the partial pressure of PCl3 will be

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Q. Phosphorus pentachloride dissociates as follows in a closed reaction vessel,
$PCl_{5\left(g\right)} {\rightleftharpoons} PCl_{3\left(g\right)}+Cl_{2\left(g\right)}$
If total pressure at equilibrium of the reaction mixture is $p$ and degree of dissociation of $PCl_{5}$ is $x$, the partial pressure of $PCl_{3}$ will be

UP CPMTUP CPMT 2012

Solution:

$\underset{\text{(1-x)}}{\ce{PCl5_{(g)}}} \ce{<=>}$ $\underset{\text{x}}{\ce{PCl3_{(g)}}}\,+$ $\underset{\text{x}}{\ce{Cl2_{(g)}}}$
Total number of moles at equilibrium
$= ( 1 - x) + x + x = 1 + x$
$p_{PCl_3}=\left(\frac{x}{1+x}\right) \times p$