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Q. $pH$ of $HCl$ (conc. $0.1 mol / L$ ) is one. Compute the $pH$ of $0.05 mol / L$ solution of $H _{2} SO _{4}$ :

Equilibrium

Solution:

Normality of $H _{2} SO _{4}=0.05 \times 2=0.1 \,N$

$pH =-\log \left[ H ^{+}\right]$

$=-\log \left[10^{-1}\right]=1$