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Q. pH of a mixture containing $0.10 M X^-$ (base) and $0.20 M\,HX$ with $p K_{b}(X)=4$ is:

Equilibrium

Solution:

By Henderson's equation,
$pOH =p K_{ b }+\log \frac{[H X]}{\left[X^{-}\right]}=4+\log 2$
$\therefore pH =14- pOH =10-\log 2 .$