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  4. pH of a 0.1 M monobasic acid is found to be 2. Hence, its osmotic pressure at a given temperature T K is

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Q. pH of a 0.1 M monobasic acid is found to be 2. Hence, its osmotic pressure at a given temperature T K is

Solutions

Solution:

$p$H = 2
$\therefore $ $[H^+] = 10^{-2}$
$C\alpha = 10^{-2} \, \alpha = \frac{10^{-2}}{10^{-1}} = 10^{-1}$
$i = 1 + \alpha $
$i = 1 + 0.1 = 1.1 $
$\pi V = in RT \, \pi = i \left( \frac{n}{V} \right) RT$
= $1.1 \times 0.1 \times RT $ = 0.11 RT.