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  4. pH of 10-7 textM NaOH is:

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Q. pH of $ {{10}^{-7}}\text{M NaOH} $ is:

VMMC MedicalVMMC Medical 2003

Solution:

Given-that, $ [O{{H}^{-}}]={{10}^{-7}}+{{10}^{-7}} $ (from water) $ \therefore $ $ [O{{H}^{-}}]=2\times {{10}^{-7}} $ $ \therefore $ $ pOH=-\log [O{{H}^{-}}] $ $ =-\log 2\times {{10}^{7}} $ $ =6.6990 $ $ \therefore $ $ pH=14-6.6990 $ $ =7.3010 $