Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $pH$ of $10^{-10} M\, HCl$ solution at $25^{\circ} C$ is approximately _____

Equilibrium

Solution:

$\left[ H ^{+}\right]$in $10^{-10} M HCl$ solution is $10^{-7}+10^{-10} \approx 10^{-7}$
Hence $pH =-\log 10^{-7}=+7$