1. Tardigrade
  2. Question
  3. Chemistry
  4. Ph -NH2 xrightarrow[0-5°C] NaNO2/HCl xrightarrow[dil.HCl]ph-NH2 (X) Find the sum of number of nitrogen atoms present in (X) and the total number of stereoisomers of (X) formed

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Q. $Ph -NH_{2} \xrightarrow[{0-5^{\circ}C}]{ NaNO_{2}/HCl }\, \xrightarrow[{dil.HCl}]{ph-NH_{2} }(X)$
Find the sum of number of nitrogen atoms present in $(X)$ and the total number of stereoisomers of $(X)$ formed

Amines

Solution:

$ph-NH_{2} \xrightarrow[{0-5^{\circ}C}]{NaNO_{2}/HCl} ph- \overset{+}{N_{2}}\overset{-}{Cl}$
image
No. of N-atoms in X is 3
No. of stereoisomers = 2 (syn/anti)