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  4. Ph -NH2 xrightarrow[0°C]HNO2 xrightarrow[BF3]HF B xrightarrowΔ C,C is

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Q. $Ph -NH_{2} \xrightarrow[{0^{\circ}C}]{HNO_2} \xrightarrow[{BF_3}]{HF} B\xrightarrow{\Delta} C,C$ is

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Solution:

$Ph -NH_{2} \xrightarrow[{0^{\circ}C}]{HNO_2} PhN_2Cl \xrightarrow[{BF_3/ \Delta}]{HF} Ph -F$