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Q. $Ph - CH = CH - Ph \xrightarrow[CCl_4]{Cl_2} X \xrightarrow{2NaNH_2} Y \xrightarrow[BaSO_4]{H_2 + Pd } Z$ Product $Z$ is

Hydrocarbons

Solution:

$Ph - CH = CH - Ph \underset{\text{(Antiaddition)}}{\xrightarrow[CCl_4]{Cl_2}}$
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