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  4. Ph - CH2 - CH2 - C ≡ C - CH3 ->[Na/NH3] ->[Cl2/hv]

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Q. $\ce{Ph - CH_2 - CH_2 - C \equiv C - CH_3 ->[Na/NH_3] ->[Cl_2/hv]}$

Solution:

Correct answer is (b)

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