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Chemistry
PH4I + NaOH forms
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Q. $PH_4I + NaOH$ forms
AIPMT
AIPMT 1991
The p-Block Elements - Part2
A
$PH_3$
73%
B
$NH_3$
10%
C
$P_4O_6$
10%
D
$P_4O_10$
6%
Solution:
When $PH_4I$ and NaOH react, phosphine gas is obtained.
$PH_4I + NaOH \, \longrightarrow \, PH_3 + Nal + H_2O$