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Q. Peroxide ion

CMC MedicalCMC Medical 2014

Solution:

Peroxide ion is $ O_{2}^{2-}. $ $ O_{2}^{2-}(18)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2} $ $ \pi 2p_{x}^{2}\approx \pi 2p_{y}^{2},\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{2} $ Bond order $ =\frac{{{N}_{b}}-{{N}_{a}}}{2} $ $ =\frac{10-8}{2}=1 $ It contains four completely filled anti bonding molecular orbitals. Since, all the electrons are paired, $ O_{2}^{2-} $ is diamagnetic. Peroxide ion is isoelectronic with argon, not with neon.