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  4. Percentage of sulphur present in any sample can be calculated as =(32 × m1 × 100/233 × m). Here, m1 refers to

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Q. Percentage of sulphur present in any sample can be calculated as $=\frac{32 \times m_{1} \times 100}{233 \times m}$.
Here, $m_{1}$ refers to

Organic Chemistry – Some Basic Principles and Techniques

Solution:

Correct answer is (a) mass of barium sulphate formed