1. Tardigrade
  2. Question
  3. Chemistry
  4. Pauling developed an equation relating bond and the electronegativity difference. |xA-xB| of the bonded atoms A and B viz: percentage ionic character =16(D x)-3.5(D x)2. Calculate (D x)=|xA-xB| for 15 % ionic character.

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Q. Pauling developed an equation relating bond and the electronegativity difference. $\left|x_{A}-x_{B}\right|$ of the bonded atoms $A$ and $B$ viz : percentage ionic character $=16(D x)-3.5(D x)^{2}$. Calculate $(D x)=\left|x_{A}-x_{B}\right|$ for $15 \%$ ionic character.

Chemical Bonding and Molecular Structure

Solution:

$35( Dx )^{2}-160 Dx +150=0$
so $Dx =\frac{160 \pm \sqrt{25600-21000}}{70}$
$=\frac{160 \pm \sqrt{4600}}{70}=1.2$