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Q.
''Pascal-second'' has the dimensions of:
AFMCAFMC 2005Physical World, Units and Measurements
Solution:
Pascal is unit of pressure.
Pascal is unit of pressure, hence its dimensional formula is $\left[ ML ^{-1} T ^{-2}\right.$ ]
$\therefore $ Dimensional formula of Pascal-second is $\left[ ML ^{-1} T ^{-1}\right]$
From the formula of coefficient of viscosity, we have
$\eta=\frac{F}{A(\Delta v / \Delta z)}$
where $F$ is force, $A$ is area and $\frac{\Delta v}{\Delta z}$ is velocity gradient.
$\therefore $ Dimensions of $\eta =\frac{\left[ MLT ^{-2}\right]}{\left[ L ^{2}\right]\left[ LT ^{-1} / L \right]}$
$=\left[ ML ^{-1} T ^{-1}\right]$
Hence, Pascal-second has dimensions of coefficient of viscosity.