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Q. $P-V$ graph of an ideal gas is as shown in the diagram. Work done by the gas in the process $ABCD$ is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$W_{A B }=-P_{0}V_{0}$
$W_{B C}=0$
$W_{A B C D}=-P_{0}V_{0}+0+4P_{0}V_{0}$
$\therefore $ $W_{A B C D }=-P_{0}V_{0}+0+4P_{0}V_{0}$
$=3P_{0}V_{0}$