1. Tardigrade
  2. Question
  3. Chemistry
  4. p Ka of CH 3 COOH =4.74, P ka of ClCH 2 COOH =2.88 Thus, difference in pH of 0.01 M solution of CH 3 COOH and ClCH 2 COOH solution, is

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Q. $p K_{a}$ of $CH _{3} COOH =4.74, P k_{a}$ of $ClCH _{2} COOH =2.88$ Thus, difference in $pH$ of $0.01 \,M$ solution of $CH _{3} COOH$ and $ClCH _{2} COOH$ solution, is

Equilibrium

Solution:

$CH _{3} COOH + H _{2} O \rightleftharpoons CH _{3} COO ^{-}+ H _{3} O ^{+}$

$ClCH _{2} COOH + H _{2} O \rightleftharpoons ClCH _{2} COO ^{-}+ H _{3} O ^{+}$

Both are weak acid but $\left( ClCH _{2} COOH \right)$ is stronger than $CH _{3} COOH$

$pH =\frac{1}{2}\left[p K_{a}-\log C\right]$

$pH =\frac{p K_{a}}{2}-\frac{\log C}{2}$

$pH \left( CH _{3} COOH \right)=\frac{4.74}{2}-\frac{\log 0.01}{2}$

$pH \left( ClCH _{2} COOH \right)=\frac{2.88}{2}-\frac{\log 0.01}{2}$

$\therefore $ Difference in $pH 2.37-1.44=0.93$