1. Tardigrade
  2. Question
  3. Chemistry
  4. p-Amino- N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue, coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate(III) leads to a brown coloration due to the formation of Z. The compound Y is

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Q. $p$-Amino- $N, N$-dimethylaniline is added to a strongly acidic solution of $X$. The resulting solution is treated with a few drops of aqueous solution of $Y$ to yield blue, coloration due to the formation of methylene blue. Treatment of the aqueous solution of $Y$ with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of $Y$ with the solution of potassium hexacyanoferrate(III) leads to a brown coloration due to the formation of $Z$.

The compound $Y$ is

JEE AdvancedJEE Advanced 2009

Solution:

$\underset{(X)}{Na_2}S + 2H^+ \to H_2S + 2Na^+$
image
$4FeCl_3+ 3K_4[\overset{II}{F}e(CN)_6] \to \underset{\text{Intence blue}}{Fe_4[Fe(CN)_6]_3} + 2KCl$
$FeCl_3 + K_3[Fe(CN)_6] \to \underset{\text{Brown coloration}}{Fe[Fe(CN)_6] } + 3KCl$
$(Y) - FeCl_3$