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Q. Oxygen occurs in nature as a mixture of isotopes $^{16}O, ^{17}O$ and $^{18}O$ having atomic masses of $15.995\, u, 16.999\, u$ and $17.999\, u$ and relative abundance of $99.763\%, 0.037\%$ and $0.200\%$ respectively. What is the average atomic mass of oxygen?

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Solution:

Average atomic mass of oxygen
$=\frac{\left(99.763\times15.995\right)+\left(0.037\times16.999\right)+\left(0.200\times17.999\right)}{100} $
$= 15.999\, u$