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  4. Oxidation state of phosphorus in PO43- , P4O10 and P2O74- is :

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Q. Oxidation state of phosphorus in $ PO_4^{3- } , P_4O_{10}$ and $P_2O_7^{4-}$ is :

Redox Reactions

Solution:

Oxidation number of oxygen in these compounds is $-2$. So we can find oxidation number of phosphorus.
In $PO _{4}^{3-}, x +4(-2)=-3, x =+5$
In $P _{4} O _{10}, 4( x )+10(-2)=0, x =+5$
In $P _{2} O _{7}^{-2}, 2( x )+7(-2)=-4, x =+5$