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Chemistry
Oxidation state of oxygen atom in potassium superoxide is
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Q. Oxidation state of oxygen atom in potassium superoxide is
Redox Reactions
A
$0$
9%
B
$-\frac{1}{2}$
55%
C
$- 1$
19%
D
$- 2$
17%
Solution:
In potassium superoxide (K02) oxygen shows $-\frac{1}{2}$ oxidation state