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Chemistry
Oxidation state of Cl in CaOCl2 is/are
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Q. Oxidation state of Cl in $CaOCl_2$ is/are
Redox Reactions
A
Zero
52%
B
+1
8%
C
-1
11%
D
+1,-1
29%
Solution:
$CaOCI_2$ is actually $Ca^{2+} (OCI)^{+1^-}CI^{-1^-}$ =O.N of two Cl atoms are +1 and -1