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Chemistry
Oxidation of 1-butene with hot KMnO4 solution produces
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Q. Oxidation of 1-butene with hot $KMnO_4$ solution produces
Hydrocarbons
A
$CH_3CH_2COOH + HCOOH$
8%
B
$CH_3CH_2COOH + CO_2$
80%
C
$CH_3COOH + CO_2$
7%
D
$(CH_3)_2C=O + CO_2$
5%
Solution:
$\quad CH _{3} CH _{2} COOH + CO _{2}$
Reaction involving in Oxidation of 1 -butene with hot $KMnO _{4}$ solution is:
$CH _{3} CH _{2} CH = CH _{2} \stackrel{ hot KMnO _{4}}{\longrightarrow } CH _{3} CH _{2} CH ( OH ) CH _{2} OH \stackrel{[ O ]}{\longrightarrow } CH _{3} CH _{2} COOH +$
HCOOH (unstable)
$H C O O H \stackrel{[ O ]}{\longrightarrow } C O _{2}+ H _{2} O$
thus, final product is $CH _{3} CH _{2} COOH + CO _{2}$