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Q. Oxidation of 1-butene with hot $KMnO_4$ solution produces

Hydrocarbons

Solution:

$\quad CH _{3} CH _{2} COOH + CO _{2}$

Reaction involving in Oxidation of 1 -butene with hot $KMnO _{4}$ solution is:

$CH _{3} CH _{2} CH = CH _{2} \stackrel{ hot KMnO _{4}}{\longrightarrow } CH _{3} CH _{2} CH ( OH ) CH _{2} OH \stackrel{[ O ]}{\longrightarrow } CH _{3} CH _{2} COOH +$

HCOOH (unstable)

$H C O O H \stackrel{[ O ]}{\longrightarrow } C O _{2}+ H _{2} O$

thus, final product is $CH _{3} CH _{2} COOH + CO _{2}$