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  4. Oxidation numbers of Mn in its compounds MnCl2, Mn(OH)3, MnO2 and KMnO4 respectively are

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Q. Oxidation numbers of Mn in its compounds $MnCl_2$, $Mn(OH)_3$, $MnO_2$ and $KMnO_4$ respectively are

Redox Reactions

Solution:

$MnCl_{2} \to x + \left(-2\right) = 0 \Rightarrow x = +2$
$Mn\left(OH\right)_{3} \to x + \left(-3\right) = 0 \Rightarrow x = +3$
$MnO_{2} \to x + \left(-4\right) = 0 \Rightarrow x = +4$
$KMnO_{4} \to ^{ }+1 + x + \left(-8\right) = 0 \Rightarrow x = +7$