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  4. Oxidation number of sulphur in H2S2O8 is:

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Q. Oxidation number of sulphur in $ {{H}_{2}}{{S}_{2}}{{O}_{8}} $ is:

MGIMS WardhaMGIMS Wardha 2005

Solution:

In $ {{H}_{2}}{{S}_{2}}{{O}_{8}} $ (morshall?s acid), two O-atom have-1 oxidation state each (peroxide Imkage) and rest six O-atom have-2 oxidation state. Hence $ 2(+1)+2x+2(-1)+6(-2)=0 $ $ 2+2x-2-12=0 $ $ 2x=12 $ $ x=+6 $