Q. Oxidation number of sulphur in Caros acid is
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Solution:
Caros acid is $ {{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{5}}}\text{.} $ It has a peroxide linkage, so, oxidation of S is calculated as
Let the oxidation state of S is $ x. $ $ {{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{5}}} $ (one peroxide bond) $ +2+x+3(-2)+1(-2)=0 $ $ 2+x-6-2=0 $ $ x-6=0 $ $ x=+\,6 $
