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Q. Oxidation number of $S$ in $ SO_{4}^{2-}: $

Bihar CECEBihar CECE 2005Redox Reactions

Solution:

The sum of oxidation states of all elements in an ion is equal to charge on it. Let the oxidation state of $S$ in $SO _{4}^{2-}=x$
$\therefore x+(-2 \times 4)=-2$
or $x=+6$