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Chemistry
Oxidation number of S in H 2 SO 5 is 6 . This is observed because -
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Q. Oxidation number of $S$ in $H _{2} SO _{5}$ is $6 .$ This is observed because -
Redox Reactions
A
There are five oxygen atoms in the molecule
B
The hydrogen atom is directly linked with non-metal
C
There is peroxide linkage in the molecule
D
The sulphur atom shows co-ordinate linkage
Solution:
$H _{2} SO _{5}$
The $O . S$ of $S$ sulphur is $+6$. This is because there is a peroxide link in the molecule.