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  4. Oxidation number of nitrogen in which among the oxides of nitrogen is the lowest ?

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Q. Oxidation number of nitrogen in which among the oxides of nitrogen is the lowest ?

MHT CETMHT CET 2014

Solution:

(a) Nitric oxide, NO $x-2=0$
$\Rightarrow x=+2$

(b) Nitrous oxide, $N _{2} O 2 x-2=0$
$\Rightarrow x=+1$

(c) Nitrogen dioxide, $NO _{2}$

$x+2(-2)=0 \Rightarrow x=+4$

(d) Nitrogen trioxide $NO _{3}$

$x+2 x(-3)=0$

$\Rightarrow x=+6$

Thus, in nitrous oxide, oxidation number of nitrogen is lowest.