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  4. Oxidation number of Fe in K3[Fe(CN)6] is:

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Q. Oxidation number of Fe in $ {{K}_{3}}[Fe{{(CN)}_{6}}] $ is:

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Solution:

Let oxidation number of Fe in $ {{K}_{3}}[Fe{{(N)}_{6}}] $ is x. $ (+1\times 3)+x+(-1\times 6)=0 $ $ 3+x-6=0 $ $ x=3 $