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Q. Oxidation number of $Cr$ in $Cr_{2} O^{2-}_{7}$ is

UP CPMTUP CPMT 2012Redox Reactions

Solution:

Let the oxidation number of $Cr$ in $Cr_{2}O^{2-}_{7}$ is $x$.
$2x + \left(7 \times -2 \right) = -2$
$2x = - 2 + 14$ or $x - 12/2 = + 6$