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Q.
Oxidation number of $Cl$ in $NOClO_4$ is
Redox Reactions
Solution:
Calculate oxidation number of $Cl$ in $NOClO_4$ by assuming $ClO_4^ -$ and $NO^+$.
Oxidation number of oxygen is $-2$, then oxidation number of chlorine in $ClO_4^ -$ is
$x + 4$(oxidation number of oxygen) $= -1$
$x + 4(-2) = -1 ⇒ x - 8 = -1$
$⇒ x = -1 + 8 = +7$.