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  4. Oxidation number of aluminium in textN texta text3 textAl textF text6 is:

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Q. Oxidation number of aluminium in $ \text{N}{{\text{a}}_{\text{3}}}\text{Al}{{\text{F}}_{\text{6}}} $ is:

VMMC MedicalVMMC Medical 2002

Solution:

In $ \text{N}{{\text{a}}_{\text{3}}}\text{Al}{{\text{F}}_{\text{6}}} $ $ (+1\times 3)+x+(-1\times 6)=0 $ $ 3+x-6=0 $ $ x=+3 $ $ \therefore $ Oxidation number of Al is $ +3. $