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Q. Oxidation number $Fe$ in $K_{3}[Fe(CN)_{6}]$ is:

JIPMERJIPMER 2004

Solution:

Let, oxidation number of $Fe$ be '$x$'.
$\therefore 3\left( +1 \right)+x+6\left( -1 \right)=0$
$3 + x- 6=0$
$x = +\,3$